Optimal. Leaf size=429 \[ \frac{2 a^3 \left (11 A d (3 c-19 d)-B \left (15 c^2-65 c d+194 d^2\right )\right ) \cos (e+f x) (c+d \sin (e+f x))^3}{693 d^3 f \sqrt{a \sin (e+f x)+a}}-\frac{2 a^3 \left (15 c^2+10 c d+7 d^2\right ) \left (11 A d \left (c^2-10 c d+73 d^2\right )-B \left (-40 c^2 d+5 c^3+169 c d^2-710 d^3\right )\right ) \cos (e+f x)}{3465 d^3 f \sqrt{a \sin (e+f x)+a}}-\frac{4 a^2 (5 c-d) \left (11 A d \left (c^2-10 c d+73 d^2\right )-B \left (-40 c^2 d+5 c^3+169 c d^2-710 d^3\right )\right ) \cos (e+f x) \sqrt{a \sin (e+f x)+a}}{3465 d^2 f}+\frac{2 a^2 (-11 A d+5 B c-14 B d) \cos (e+f x) \sqrt{a \sin (e+f x)+a} (c+d \sin (e+f x))^3}{99 d^2 f}-\frac{2 a \left (11 A d \left (c^2-10 c d+73 d^2\right )-B \left (-40 c^2 d+5 c^3+169 c d^2-710 d^3\right )\right ) \cos (e+f x) (a \sin (e+f x)+a)^{3/2}}{1155 d f}-\frac{2 a B \cos (e+f x) (a \sin (e+f x)+a)^{3/2} (c+d \sin (e+f x))^3}{11 d f} \]
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Rubi [A] time = 1.06576, antiderivative size = 429, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 37, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.135, Rules used = {2976, 2981, 2761, 2751, 2646} \[ \frac{2 a^3 \left (11 A d (3 c-19 d)-B \left (15 c^2-65 c d+194 d^2\right )\right ) \cos (e+f x) (c+d \sin (e+f x))^3}{693 d^3 f \sqrt{a \sin (e+f x)+a}}-\frac{2 a^3 \left (15 c^2+10 c d+7 d^2\right ) \left (11 A d \left (c^2-10 c d+73 d^2\right )-B \left (-40 c^2 d+5 c^3+169 c d^2-710 d^3\right )\right ) \cos (e+f x)}{3465 d^3 f \sqrt{a \sin (e+f x)+a}}-\frac{4 a^2 (5 c-d) \left (11 A d \left (c^2-10 c d+73 d^2\right )-B \left (-40 c^2 d+5 c^3+169 c d^2-710 d^3\right )\right ) \cos (e+f x) \sqrt{a \sin (e+f x)+a}}{3465 d^2 f}+\frac{2 a^2 (-11 A d+5 B c-14 B d) \cos (e+f x) \sqrt{a \sin (e+f x)+a} (c+d \sin (e+f x))^3}{99 d^2 f}-\frac{2 a \left (11 A d \left (c^2-10 c d+73 d^2\right )-B \left (-40 c^2 d+5 c^3+169 c d^2-710 d^3\right )\right ) \cos (e+f x) (a \sin (e+f x)+a)^{3/2}}{1155 d f}-\frac{2 a B \cos (e+f x) (a \sin (e+f x)+a)^{3/2} (c+d \sin (e+f x))^3}{11 d f} \]
Antiderivative was successfully verified.
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Rule 2976
Rule 2981
Rule 2761
Rule 2751
Rule 2646
Rubi steps
\begin{align*} \int (a+a \sin (e+f x))^{5/2} (A+B \sin (e+f x)) (c+d \sin (e+f x))^2 \, dx &=-\frac{2 a B \cos (e+f x) (a+a \sin (e+f x))^{3/2} (c+d \sin (e+f x))^3}{11 d f}+\frac{2 \int (a+a \sin (e+f x))^{3/2} (c+d \sin (e+f x))^2 \left (\frac{1}{2} a (11 A d+3 B (c+2 d))-\frac{1}{2} a (5 B c-11 A d-14 B d) \sin (e+f x)\right ) \, dx}{11 d}\\ &=\frac{2 a^2 (5 B c-11 A d-14 B d) \cos (e+f x) \sqrt{a+a \sin (e+f x)} (c+d \sin (e+f x))^3}{99 d^2 f}-\frac{2 a B \cos (e+f x) (a+a \sin (e+f x))^{3/2} (c+d \sin (e+f x))^3}{11 d f}+\frac{4 \int \sqrt{a+a \sin (e+f x)} (c+d \sin (e+f x))^2 \left (\frac{1}{4} a^2 \left (11 A d (c+15 d)-B \left (5 c^2-11 c d-138 d^2\right )\right )-\frac{1}{4} a^2 \left (11 A (3 c-19 d) d-B \left (15 c^2-65 c d+194 d^2\right )\right ) \sin (e+f x)\right ) \, dx}{99 d^2}\\ &=\frac{2 a^3 \left (11 A (3 c-19 d) d-B \left (15 c^2-65 c d+194 d^2\right )\right ) \cos (e+f x) (c+d \sin (e+f x))^3}{693 d^3 f \sqrt{a+a \sin (e+f x)}}+\frac{2 a^2 (5 B c-11 A d-14 B d) \cos (e+f x) \sqrt{a+a \sin (e+f x)} (c+d \sin (e+f x))^3}{99 d^2 f}-\frac{2 a B \cos (e+f x) (a+a \sin (e+f x))^{3/2} (c+d \sin (e+f x))^3}{11 d f}+\frac{\left (a^2 \left (11 A d \left (c^2-10 c d+73 d^2\right )-B \left (5 c^3-40 c^2 d+169 c d^2-710 d^3\right )\right )\right ) \int \sqrt{a+a \sin (e+f x)} (c+d \sin (e+f x))^2 \, dx}{231 d^3}\\ &=-\frac{2 a \left (11 A d \left (c^2-10 c d+73 d^2\right )-B \left (5 c^3-40 c^2 d+169 c d^2-710 d^3\right )\right ) \cos (e+f x) (a+a \sin (e+f x))^{3/2}}{1155 d f}+\frac{2 a^3 \left (11 A (3 c-19 d) d-B \left (15 c^2-65 c d+194 d^2\right )\right ) \cos (e+f x) (c+d \sin (e+f x))^3}{693 d^3 f \sqrt{a+a \sin (e+f x)}}+\frac{2 a^2 (5 B c-11 A d-14 B d) \cos (e+f x) \sqrt{a+a \sin (e+f x)} (c+d \sin (e+f x))^3}{99 d^2 f}-\frac{2 a B \cos (e+f x) (a+a \sin (e+f x))^{3/2} (c+d \sin (e+f x))^3}{11 d f}+\frac{\left (2 a \left (11 A d \left (c^2-10 c d+73 d^2\right )-B \left (5 c^3-40 c^2 d+169 c d^2-710 d^3\right )\right )\right ) \int \sqrt{a+a \sin (e+f x)} \left (\frac{1}{2} a \left (5 c^2+3 d^2\right )+a (5 c-d) d \sin (e+f x)\right ) \, dx}{1155 d^3}\\ &=-\frac{4 a^2 (5 c-d) \left (11 A d \left (c^2-10 c d+73 d^2\right )-B \left (5 c^3-40 c^2 d+169 c d^2-710 d^3\right )\right ) \cos (e+f x) \sqrt{a+a \sin (e+f x)}}{3465 d^2 f}-\frac{2 a \left (11 A d \left (c^2-10 c d+73 d^2\right )-B \left (5 c^3-40 c^2 d+169 c d^2-710 d^3\right )\right ) \cos (e+f x) (a+a \sin (e+f x))^{3/2}}{1155 d f}+\frac{2 a^3 \left (11 A (3 c-19 d) d-B \left (15 c^2-65 c d+194 d^2\right )\right ) \cos (e+f x) (c+d \sin (e+f x))^3}{693 d^3 f \sqrt{a+a \sin (e+f x)}}+\frac{2 a^2 (5 B c-11 A d-14 B d) \cos (e+f x) \sqrt{a+a \sin (e+f x)} (c+d \sin (e+f x))^3}{99 d^2 f}-\frac{2 a B \cos (e+f x) (a+a \sin (e+f x))^{3/2} (c+d \sin (e+f x))^3}{11 d f}+\frac{\left (a^2 \left (15 c^2+10 c d+7 d^2\right ) \left (11 A d \left (c^2-10 c d+73 d^2\right )-B \left (5 c^3-40 c^2 d+169 c d^2-710 d^3\right )\right )\right ) \int \sqrt{a+a \sin (e+f x)} \, dx}{3465 d^3}\\ &=-\frac{2 a^3 \left (15 c^2+10 c d+7 d^2\right ) \left (11 A d \left (c^2-10 c d+73 d^2\right )-B \left (5 c^3-40 c^2 d+169 c d^2-710 d^3\right )\right ) \cos (e+f x)}{3465 d^3 f \sqrt{a+a \sin (e+f x)}}-\frac{4 a^2 (5 c-d) \left (11 A d \left (c^2-10 c d+73 d^2\right )-B \left (5 c^3-40 c^2 d+169 c d^2-710 d^3\right )\right ) \cos (e+f x) \sqrt{a+a \sin (e+f x)}}{3465 d^2 f}-\frac{2 a \left (11 A d \left (c^2-10 c d+73 d^2\right )-B \left (5 c^3-40 c^2 d+169 c d^2-710 d^3\right )\right ) \cos (e+f x) (a+a \sin (e+f x))^{3/2}}{1155 d f}+\frac{2 a^3 \left (11 A (3 c-19 d) d-B \left (15 c^2-65 c d+194 d^2\right )\right ) \cos (e+f x) (c+d \sin (e+f x))^3}{693 d^3 f \sqrt{a+a \sin (e+f x)}}+\frac{2 a^2 (5 B c-11 A d-14 B d) \cos (e+f x) \sqrt{a+a \sin (e+f x)} (c+d \sin (e+f x))^3}{99 d^2 f}-\frac{2 a B \cos (e+f x) (a+a \sin (e+f x))^{3/2} (c+d \sin (e+f x))^3}{11 d f}\\ \end{align*}
Mathematica [B] time = 6.61678, size = 891, normalized size = 2.08 \[ \frac{(a (\sin (e+f x)+1))^{5/2} \left (-277200 A \cos \left (\frac{1}{2} (e+f x)\right ) c^2-207900 B \cos \left (\frac{1}{2} (e+f x)\right ) c^2-46200 A \cos \left (\frac{3}{2} (e+f x)\right ) c^2-50820 B \cos \left (\frac{3}{2} (e+f x)\right ) c^2+5544 A \cos \left (\frac{5}{2} (e+f x)\right ) c^2+13860 B \cos \left (\frac{5}{2} (e+f x)\right ) c^2+1980 B \cos \left (\frac{7}{2} (e+f x)\right ) c^2+277200 A \sin \left (\frac{1}{2} (e+f x)\right ) c^2+207900 B \sin \left (\frac{1}{2} (e+f x)\right ) c^2-46200 A \sin \left (\frac{3}{2} (e+f x)\right ) c^2-50820 B \sin \left (\frac{3}{2} (e+f x)\right ) c^2-5544 A \sin \left (\frac{5}{2} (e+f x)\right ) c^2-13860 B \sin \left (\frac{5}{2} (e+f x)\right ) c^2+1980 B \sin \left (\frac{7}{2} (e+f x)\right ) c^2-415800 A d \cos \left (\frac{1}{2} (e+f x)\right ) c-360360 B d \cos \left (\frac{1}{2} (e+f x)\right ) c-101640 A d \cos \left (\frac{3}{2} (e+f x)\right ) c-92400 B d \cos \left (\frac{3}{2} (e+f x)\right ) c+27720 A d \cos \left (\frac{5}{2} (e+f x)\right ) c+33264 B d \cos \left (\frac{5}{2} (e+f x)\right ) c+3960 A d \cos \left (\frac{7}{2} (e+f x)\right ) c+9900 B d \cos \left (\frac{7}{2} (e+f x)\right ) c-1540 B d \cos \left (\frac{9}{2} (e+f x)\right ) c+415800 A d \sin \left (\frac{1}{2} (e+f x)\right ) c+360360 B d \sin \left (\frac{1}{2} (e+f x)\right ) c-101640 A d \sin \left (\frac{3}{2} (e+f x)\right ) c-92400 B d \sin \left (\frac{3}{2} (e+f x)\right ) c-27720 A d \sin \left (\frac{5}{2} (e+f x)\right ) c-33264 B d \sin \left (\frac{5}{2} (e+f x)\right ) c+3960 A d \sin \left (\frac{7}{2} (e+f x)\right ) c+9900 B d \sin \left (\frac{7}{2} (e+f x)\right ) c+1540 B d \sin \left (\frac{9}{2} (e+f x)\right ) c-180180 A d^2 \cos \left (\frac{1}{2} (e+f x)\right )-159390 B d^2 \cos \left (\frac{1}{2} (e+f x)\right )-46200 A d^2 \cos \left (\frac{3}{2} (e+f x)\right )-43890 B d^2 \cos \left (\frac{3}{2} (e+f x)\right )+16632 A d^2 \cos \left (\frac{5}{2} (e+f x)\right )+17325 B d^2 \cos \left (\frac{5}{2} (e+f x)\right )+4950 A d^2 \cos \left (\frac{7}{2} (e+f x)\right )+6435 B d^2 \cos \left (\frac{7}{2} (e+f x)\right )-770 A d^2 \cos \left (\frac{9}{2} (e+f x)\right )-1925 B d^2 \cos \left (\frac{9}{2} (e+f x)\right )-315 B d^2 \cos \left (\frac{11}{2} (e+f x)\right )+180180 A d^2 \sin \left (\frac{1}{2} (e+f x)\right )+159390 B d^2 \sin \left (\frac{1}{2} (e+f x)\right )-46200 A d^2 \sin \left (\frac{3}{2} (e+f x)\right )-43890 B d^2 \sin \left (\frac{3}{2} (e+f x)\right )-16632 A d^2 \sin \left (\frac{5}{2} (e+f x)\right )-17325 B d^2 \sin \left (\frac{5}{2} (e+f x)\right )+4950 A d^2 \sin \left (\frac{7}{2} (e+f x)\right )+6435 B d^2 \sin \left (\frac{7}{2} (e+f x)\right )+770 A d^2 \sin \left (\frac{9}{2} (e+f x)\right )+1925 B d^2 \sin \left (\frac{9}{2} (e+f x)\right )-315 B d^2 \sin \left (\frac{11}{2} (e+f x)\right )\right )}{55440 f \left (\cos \left (\frac{1}{2} (e+f x)\right )+\sin \left (\frac{1}{2} (e+f x)\right )\right )^5} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.928, size = 257, normalized size = 0.6 \begin{align*}{\frac{ \left ( 2+2\,\sin \left ( fx+e \right ) \right ){a}^{3} \left ( -1+\sin \left ( fx+e \right ) \right ) \left ( 315\,B{d}^{2}\sin \left ( fx+e \right ) \left ( \cos \left ( fx+e \right ) \right ) ^{4}+ \left ( -990\,Acd-1430\,A{d}^{2}-495\,B{c}^{2}-2860\,Bcd-2405\,B{d}^{2} \right ) \left ( \cos \left ( fx+e \right ) \right ) ^{2}\sin \left ( fx+e \right ) + \left ( 3234\,A{c}^{2}+8580\,Acd+4642\,A{d}^{2}+4290\,B{c}^{2}+9284\,Bcd+4930\,B{d}^{2} \right ) \sin \left ( fx+e \right ) + \left ( 385\,A{d}^{2}+770\,Bcd+1120\,B{d}^{2} \right ) \left ( \cos \left ( fx+e \right ) \right ) ^{4}+ \left ( -693\,A{c}^{2}-3960\,Acd-3179\,A{d}^{2}-1980\,B{c}^{2}-6358\,Bcd-4370\,B{d}^{2} \right ) \left ( \cos \left ( fx+e \right ) \right ) ^{2}+10626\,A{c}^{2}+19140\,Acd+9218\,A{d}^{2}+9570\,B{c}^{2}+18436\,Bcd+8930\,B{d}^{2} \right ) }{3465\,f\cos \left ( fx+e \right ) }{\frac{1}{\sqrt{a+a\sin \left ( fx+e \right ) }}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (B \sin \left (f x + e\right ) + A\right )}{\left (a \sin \left (f x + e\right ) + a\right )}^{\frac{5}{2}}{\left (d \sin \left (f x + e\right ) + c\right )}^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.96476, size = 1500, normalized size = 3.5 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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